{"id":6030,"date":"2023-04-12T14:38:46","date_gmt":"2023-04-12T14:38:46","guid":{"rendered":"https:\/\/longchangchemical.com\/?p=6030"},"modified":"2023-04-12T14:38:46","modified_gmt":"2023-04-12T14:38:46","slug":"how-do-levelling-agents-level-the-paint","status":"publish","type":"post","link":"https:\/\/longchangchemical.com\/hu\/how-do-levelling-agents-level-the-paint\/","title":{"rendered":"Hogyan egyenl\u00edtik ki a fest\u00e9ket a kiegyenl\u00edt\u0151szerek?"},"content":{"rendered":"<h1><strong>Hogyan egyenl\u00edtik ki a fest\u00e9ket a kiegyenl\u00edt\u0151szerek?<\/strong><\/h1>\n<p>1\u3001Lap\u00edt\u00f3szer meghat\u00e1roz\u00e1sa<\/p>\n<p>A kiegyenl\u00edt\u0151szer egy k\u00f6z\u00f6s bevonat adal\u00e9kanyag, el\u0151seg\u00edtheti a bevonatot a sz\u00e1r\u00edt\u00e1si folyamatban, hogy sima, sima, egyenletes bevonatfilmet k\u00e9pezzen, a k\u00fcl\u00f6nb\u00f6z\u0151 t\u00edpus\u00fa bevonatok a kiegyenl\u00edt\u0151szerre alkalmazott k\u00fcl\u00f6nb\u00f6z\u0151ek.<\/p>\n<p>2\u3001A kiegyenl\u00edt\u00e9s elve (migr\u00e1ci\u00f3s mechanizmus)<\/p>\n<p>Mint kiegyenl\u00edt\u0151 szer, \u00e1ltal\u00e1ban meg kell felelnie a k\u00f6vetkez\u0151 k\u00e9t pontnak:<\/p>\n<p>2.1, \u00e9s a rendszer bizonyos fok\u00fa kompatibilit\u00e1ssal rendelkezik.<\/p>\n<p>2,2, a fel\u00fcleti fesz\u00fclts\u00e9gnek alacsonyabbnak kell lennie, mint a rendszernek.<\/p>\n<p>Ez a k\u00e9t pont befoly\u00e1solja a kiegyenl\u00edt\u0151szer migr\u00e1ci\u00f3j\u00e1t, csak a kiegyenl\u00edt\u0151szer spont\u00e1n v\u00e1ndorol a fest\u00e9kfilm fel\u00fclet\u00e9re, a kiegyenl\u00edt\u0151 hat\u00e1s el\u0151fordul\u00e1s\u00e1nak nevezhet\u0151. A migr\u00e1ci\u00f3s elv m\u00e1s adal\u00e9kanyagok migr\u00e1ci\u00f3j\u00e1ra is vonatkozik.<\/p>\n<p>A migr\u00e1ci\u00f3 elve<\/p>\n<p>A kiegyenl\u00edt\u0151 anyagok v\u00e1ndorl\u00e1sa a fizika \"legkisebb energia elv\u00e9t\" k\u00f6veti, azaz spont\u00e1n m\u00f3don \u00e1ramlanak a magas energi\u00e1j\u00fa helyr\u0151l az alacsony energi\u00e1j\u00fa helyre. Amikor a fest\u00e9ket a hordoz\u00f3fel\u00fcletre viszik fel, k\u00e9t hat\u00e1rfel\u00fclet alakul ki, a \"hordoz\u00f3 - fest\u00e9kfilm hat\u00e1rfel\u00fclet\" \u00e9s a \"fest\u00e9kfilm - leveg\u0151 hat\u00e1rfel\u00fclet\".<\/p>\n<p>Ez\u00e9rt a rendszer teljes energi\u00e1ja = (a hordoz\u00f3 fel\u00fcleti fesz\u00fclts\u00e9ge - a fest\u00e9kfilm fel\u00fcleti fesz\u00fclts\u00e9ge) + (a fest\u00e9kfilm fel\u00fcleti fesz\u00fclts\u00e9ge - a leveg\u0151 fel\u00fcleti fesz\u00fclts\u00e9ge).<\/p>\n<p>Ha a rendszerhez kiegyenl\u00edt\u0151szert adunk, \u00e9s a kiegyenl\u00edt\u0151szer a \"film-leveg\u0151 hat\u00e1rfel\u00fcletre\" v\u00e1ndorol, akkor a rendszer teljes energi\u00e1ja = (szubsztr\u00e1t fel\u00fcleti fesz\u00fclts\u00e9g - film fel\u00fcleti fesz\u00fclts\u00e9g) + (kiegyenl\u00edt\u0151szer fel\u00fcleti fesz\u00fclts\u00e9g - leveg\u0151 fel\u00fcleti fesz\u00fclts\u00e9g), mivel a kiegyenl\u00edt\u0151szer fel\u00fcleti fesz\u00fclts\u00e9ge &lt; film fel\u00fcleti fesz\u00fclts\u00e9g, a rendszer teljes energi\u00e1ja cs\u00f6kken, \u00e9s a folyamat A folyamat spont\u00e1n lefolyhat.<\/p>\n<p>Ha azonban a kiegyenl\u00edt\u0151szer a \"szubsztr\u00e1t - fest\u00e9kfilm hat\u00e1rfel\u00fcletre\" v\u00e1ndorol, a rendszer teljes energi\u00e1ja = (szubsztr\u00e1t fel\u00fcleti fesz\u00fclts\u00e9g - kiegyenl\u00edt\u0151szer fel\u00fcleti fesz\u00fclts\u00e9g) + (fest\u00e9kfilm fel\u00fcleti fesz\u00fclts\u00e9g - leveg\u0151 fel\u00fcleti fesz\u00fclts\u00e9g), mivel a kiegyenl\u00edt\u0151szer fel\u00fcleti fesz\u00fclts\u00e9ge &lt; fest\u00e9kfilm fel\u00fcleti fesz\u00fclts\u00e9g, \u00edgy a rendszer teljes energi\u00e1ja megn\u0151, \u00e9s a folyamat nem tud spont\u00e1n lezajlani.<\/p>\n<p>Term\u00e9szetesen a molekul\u00e1ris mozg\u00e1selm\u00e9let szempontj\u00e1b\u00f3l, amikor a kiegyenl\u00edt\u0151szert a rendszerhez adj\u00e1k, a molekul\u00e1k szab\u00e1lytalan mozg\u00e1sa miatt a kiegyenl\u00edt\u0151szer egy r\u00e9sze a \"szubsztr\u00e1t - fest\u00e9kfilm hat\u00e1rfel\u00fclet\" fel\u00e9 mozog, de a kiegyenl\u00edt\u0151szer ezen r\u00e9sz\u00e9nek mennyis\u00e9ge nagyon kicsi, a teljes hozz\u00e1adott mennyis\u00e9ghez k\u00e9pest elhanyagolhat\u00f3.<\/p>\n<p>3\u3001A szilikon kiegyenl\u00edt\u0151 anyag elve<\/p>\n<p>A szilikon szintez\u0151anyagok szerkezete a leggyakoribb poli\u00e9ter m\u00f3dos\u00edtott szilikonolajon alapul, amelynek szerkezeti k\u00e9plete a k\u00f6vetkez\u0151 k\u00e9plettel fejezhet\u0151 ki:<\/p>\n<p>-(SiO(CH3)2)m-(SiOCH3 (CH2CH2O)x(CH2CHCHCH3O)y)nR<\/p>\n<p>Ahol az m l\u00e1ncszegmens a szilikonolaj nem m\u00f3dos\u00edtott r\u00e9sz\u00e9t jel\u00f6li, amely a korl\u00e1tozott kompatibilit\u00e1s\u00fa l\u00e1ncszegmenshez tartozik; az n l\u00e1ncszegmens a m\u00f3dos\u00edtott r\u00e9sz, amely a kompatibilis l\u00e1ncszegmenshez tartozik; x a poli\u00e9ter m\u00f3dos\u00edtott l\u00e1ncszegmens polietil\u00e9n-oxid r\u00e9sze; y a poli\u00e9tercsoport polietil\u00e9n-oxid r\u00e9sze; m, n, x, y n\u00e9gy \u00e9rt\u00e9k hat\u00e1rozza meg a kiegyenl\u00edt\u0151szer \u00e1ltal mutatott teljes\u00edtm\u00e9nyt.<\/p>\n<p>3.1\u3001Kompatibilit\u00e1s: A szilikon kiegyenl\u00edt\u0151szerek kompatibilit\u00e1sa els\u0151sorban az m\/n \u00e9rt\u00e9k\u00e9t\u0151l f\u00fcgg. Min\u00e9l kisebb az m \/n \u00e9rt\u00e9ke (azaz min\u00e9l kisebb az inkompatibilis l\u00e1ncszegmensek tartalma), ann\u00e1l jobb a kompatibilit\u00e1s, \u00e9s min\u00e9l nagyobb az x\/y \u00e9rt\u00e9ke az m\/n r\u00f6gz\u00edtett \u00e9rt\u00e9ke alatt, ann\u00e1l jobb a kompatibilit\u00e1s, ami az\u00e9rt van, mert a poli(etil\u00e9n-oxid) kompatibilit\u00e1sa meghaladja a poli(propil\u00e9n-oxid) kompatibilit\u00e1s\u00e1t.<\/p>\n<p>3.2, \u00e9rz\u00e9s: r\u00f6gz\u00edtett xy-\u00e9rt\u00e9k eset\u00e9n a szilikon kiegyenl\u00edt\u0151szer \u00e9rz\u00e9se is els\u0151sorban az m\/n \u00e9rt\u00e9k\u00e9t\u0151l f\u00fcgg, min\u00e9l nagyobb az m\/n \u00e9rt\u00e9ke, ann\u00e1l jobb a tapint\u00e1s; m\/n \u00e9rt\u00e9ke ugyanabban az esetben, min\u00e9l nagyobb az m abszol\u00fat \u00e9rt\u00e9ke, ann\u00e1l jobb a tapint\u00e1s; ebb\u0151l a pontb\u00f3l l\u00e1that\u00f3, hogy a szilikon kiegyenl\u00edt\u0151szer eset\u00e9ben a j\u00f3 kompatibilit\u00e1s \u00e9s a j\u00f3 tapint\u00e1s gyakran ellentmond\u00e1s, mindkett\u0151 el\u00e9r\u00e9se \u00e9rdek\u00e9ben \u00e1ltal\u00e1ban az m\/n csak egy kis tartom\u00e1nyon bel\u00fcl v\u00e1laszthat\u00f3 ki.<\/p>\n<p>3.3, kiegyenl\u00edt\u0151 k\u00e9pess\u00e9g: m, n, x, y \u00e9rt\u00e9kek a kiegyenl\u00edt\u0151 hat\u00e1s hat\u00e1s\u00e1ra \u00f6sszetettebb, \u00e1ltal\u00e1ban m \/ n \u00e9rt\u00e9kek 1 \u00e9s 2 k\u00f6z\u00f6tt, amikor van egy jobb kiegyenl\u00edt\u0151 hat\u00e1s, \u00e9s egy r\u00f6gz\u00edtett m \/ n \u00e9rt\u00e9k az esetben, min\u00e9l nagyobb az x + y \u00e9rt\u00e9ke, ann\u00e1l jobb a kiegyenl\u00edt\u0151 hat\u00e1s.<\/p>\n<p>3.4, stabil hab: Ha a szil\u00edciumtartalom nagyon magas vagy nagyon alacsony, a kiegyenl\u00edt\u0151szer nem stabil hab, \u00e9s ha nagyon magas szil\u00edciumtartalm\u00fa fajt\u00e1kba ker\u00fcl, akkor kiv\u00e1l\u00f3, nem stabil hab, de valamivel kev\u00e9sb\u00e9 kompatibilis kiegyenl\u00edt\u0151szer, ha Ha a szil\u00edciumtartalom nagyon alacsony, a kiegyenl\u00edt\u0151szer teljes\u00edtm\u00e9nye nagyon j\u00f3 kompatibilit\u00e1s, nem stabil hab, de a szilikon kiegyenl\u00edt\u0151szer \u00e9rz\u00e9se nem el\u00e9g. 5.<\/p>\n<p>3.5. \u00dajrabevonhat\u00f3s\u00e1g: \u00e1ltal\u00e1ban min\u00e9l nagyobb az m+n \u00e9rt\u00e9ke \u00e9s min\u00e9l nagyobb az m\/n \u00e9rt\u00e9ke, ann\u00e1l val\u00f3sz\u00edn\u0171bb, hogy az \u00fajrabevonhat\u00f3s\u00e1gi probl\u00e9m\u00e1k jelentkeznek, a poli\u00e9ter v\u00e9gcsoport R csoport t\u00edpus\u00e1n k\u00edv\u00fcl az R csoport is hat\u00e1ssal van az \u00fajrabevonhat\u00f3s\u00e1gra.<\/p>\n<p>3.6, a matracpor ir\u00e1ny\u00edthat\u00f3s\u00e1ga: a vizsg\u00e1lat szerint a matracpor ir\u00e1ny\u00edthat\u00f3s\u00e1g\u00e1t nagyban befoly\u00e1solja az m\/n \u00e9rt\u00e9ke \u00e9s az m abszol\u00fat \u00e9rt\u00e9ke. Min\u00e9l nagyobb az m abszol\u00fat \u00e9rt\u00e9ke, ann\u00e1l jobb a matracpor ir\u00e1ny\u00edthat\u00f3s\u00e1ga.<\/p>\n<p>Okok<br \/>\nA fest\u00e9kfel\u00fcletek hajlamosak az olyan jelens\u00e9gekre, mint a zsugorod\u00e1s, a narancsb\u0151r, a fel\u00fcleti \u00e9rdess\u00e9g \u00e9s a f\u00e9nyess\u00e9g hi\u00e1nya, ami komolyan akad\u00e1lyozza az \u00faj technol\u00f3gi\u00e1k, p\u00e9ld\u00e1ul a por, a v\u00edzb\u00e1zis\u00fa \u00e9s a nagy szil\u00e1rds\u00e1g\u00fa bevonatok n\u00e9pszer\u0171s\u00edt\u00e9s\u00e9t \u00e9s alkalmaz\u00e1s\u00e1t. A fest\u00e9kekben kiegyenl\u00edt\u0151 szereket haszn\u00e1lnak e jelens\u00e9gek cs\u00f6kkent\u00e9s\u00e9re, a fest\u00e9kfilm fel\u00fclet\u00e9nek sim\u00e1v\u00e1 \u00e9s dekorat\u00edvv\u00e1 t\u00e9tel\u00e9re.<\/p>\n<p>Ennek \u00e9rdek\u00e9ben a fel\u00fcleti fesz\u00fclts\u00e9ggel f\u00fcgg \u00f6ssze.<\/p>\n<p>Fel\u00fcleti fesz\u00fclts\u00e9g<br \/>\nEgy folyad\u00e9kban a molekul\u00e1ris gravit\u00e1ci\u00f3s er\u0151k minden molekul\u00e1ra kiegyens\u00falyozottak. A folyad\u00e9k felsz\u00edn\u00e9n azonban a folyad\u00e9kf\u00e1zis molekul\u00e1inak a felsz\u00edni molekul\u00e1kra hat\u00f3 gravit\u00e1ci\u00f3s ereje nagyobb, mint a g\u00e1zf\u00e1zis molekul\u00e1inak a felsz\u00edni molekul\u00e1kra hat\u00f3 gravit\u00e1ci\u00f3s ereje, ez\u00e9rt a folyad\u00e9k belseje fel\u00e9 vonz\u00f3er\u0151 hat, \u00e9s ez a fel\u00fcleti fesz\u00fclts\u00e9g. A kiegyenl\u00edt\u0151szer hozz\u00e1ad\u00e1sakor a kiegyenl\u00edt\u0151szer fel\u00faszhat a fest\u00e9kfilm felsz\u00edn\u00e9re, hogy homogeniz\u00e1lja azt, ez az egyik kiegyenl\u00edt\u0151 mechanizmus.<\/p>\n<p>Zsugorod\u00e1s \u00e9s narancsb\u0151r<br \/>\nEnnek oka, hogy ha a folyad\u00e9k fel\u00fcleti fesz\u00fclts\u00e9ge a nedves fest\u00e9kfilm k\u00e9t pontj\u00e1n elt\u00e9r\u0151, a fest\u00e9kanyag az egyik pontr\u00f3l a m\u00e1sikra folyik, \u00edgy zsugorod\u00e1s, narancsb\u0151r stb. keletkezik. Az akril kiegyenl\u00edt\u0151szer k\u00e9pes cs\u00f6kkenteni a fel\u00fcleti fesz\u00fclts\u00e9get \u00e9s a hat\u00e1rfel\u00fcleti fesz\u00fclts\u00e9get a nedves\u00edthet\u0151s\u00e9g n\u00f6vel\u00e9se \u00e9rdek\u00e9ben, \u00e9s k\u00e9pes egyetlen molekul\u00e1ris r\u00e9teget k\u00e9pezni a fest\u00e9k fel\u00fclet\u00e9n, hogy biztos\u00edtsa a fel\u00fcleti fesz\u00fclts\u00e9g homogeniz\u00e1l\u00e1s\u00e1t a fel\u00fcleti r\u00e9szen.<\/p>\n<h2><strong><b>L\u00e9pjen kapcsolatba vel\u00fcnk most!<\/b><\/strong><\/h2>\n<h4><strong><b>Ha COA, MSDS vagy TDS-re van sz\u00fcks\u00e9ge, k\u00e9rj\u00fck, t\u00f6ltse ki el\u00e9rhet\u0151s\u00e9g\u00e9t az al\u00e1bbi \u0171rlapon, \u00e1ltal\u00e1ban 24 \u00f3r\u00e1n bel\u00fcl felvessz\u00fck \u00d6nnel a kapcsolatot. \u00d6n is k\u00fcldhet nekem e-mailt<span style=\"color: #00ccff;\"> <a style=\"color: #00ccff;\" href=\"mailto:info@longchangchemical.com\">info@longchangchemical.com<\/a><\/span> munkaid\u0151ben ( 8:30-18:00 UTC+8 H.-Szombat ) vagy haszn\u00e1lja a weboldal \u00e9l\u0151 chatj\u00e9t, hogy azonnali v\u00e1laszt kapjon.<\/b><\/strong><\/h4>","protected":false},"excerpt":{"rendered":"<p>Hogyan egyenl\u00edtik ki a fest\u00e9ket a kiegyenl\u00edt\u0151szerek? 1\u3001A kiegyenl\u00edt\u0151szer meghat\u00e1roz\u00e1sa A kiegyenl\u00edt\u0151szer egy k\u00f6z\u00f6s bevonatadal\u00e9kanyag, amely el\u0151seg\u00edtheti a bevonat sz\u00e1r\u00edt\u00e1si folyamat\u00e1t, hogy sima, sima, egyenletes bevonatfilmet k\u00e9pezzen, a kiegyenl\u00edt\u0151szerre alkalmazott k\u00fcl\u00f6nb\u00f6z\u0151 t\u00edpus\u00fa bevonatok k\u00fcl\u00f6nb\u00f6z\u0151ek. 2\u3001A kiegyenl\u00edt\u00e9s elve (migr\u00e1ci\u00f3s mechanizmus) Mint kiegyenl\u00edt\u0151szer, \u00e1ltal\u00e1ban [...]<\/p>","protected":false},"author":1,"featured_media":5984,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[143],"tags":[],"class_list":["post-6030","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-uv-light-curing-series"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v25.3.1 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>How do levelling agents level the paint? 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